CH_3-CH(CH_3)-O-C_6H_5 xrightarrow{HI/Delta} | vedclass

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Question

(B) In alkyl aryl ethers,the bond between the oxygen atom and the aromatic ring has partial double bond character due to resonance,making it stronger

Vedclass · Accepted Answer

$CH_3-CH(I)-CH_3 + C_6H_5-OH$

Vedclass · Answer

(B) In alkyl aryl ethers,the bond between the oxygen atom and the aromatic ring has partial double bond character due to resonance,making it stronger than the alkyl-oxygen bond.Therefore,when reacted with $HI$,the alkyl-oxygen bond breaks,yielding phenol and an alkyl iodide.Reaction: $C_6H_5-O-CH(CH_3)_2 + HI \xrightarrow{\Delta} C_6H_5-OH + CH_3-CH(I)-CH_3$.

$CH_3-CH(CH_3)-O-C_6H_5 \xrightarrow{HI/\Delta} (X + Y)$. $X$ and $Y$ are:

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