How many grams of NaOH are required to neutra | vedclass

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(B) The neutralization reaction is: $C_6H_5COOH + NaOH 	o C_6H_5COONa + H_2O$. The molar mass of benzoic acid $(C_6H_5COOH)$ is $122 \ g/mol$. The mo

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$4.0$

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(B) The neutralization reaction is: $C_6H_5COOH + NaOH 	o C_6H_5COONa + H_2O$. The molar mass of benzoic acid $(C_6H_5COOH)$ is $122 \ g/mol$. The molar mass of $NaOH$ is $40 \ g/mol$. Since the stoichiometry is $1:1$,the moles of $NaOH$ required equal the moles of benzoic acid. Moles of benzoic acid = $\frac{12.2 \ g}{122 \ g/mol} = 0.1 \ mol$. Moles of $NaOH$ required = $0.1 \ mol$. Mass of $NaOH$ = $0.1 \ mol 	imes 40 \ g/mol = 4.0 \ g$.

How many grams of $NaOH$ are required to neutralize $12.2 \ g$ of benzoic acid (in $g$)?

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