(A) The hydrolysis of silicon tetrachloride $(SiCl_4)$ proceeds as follows: $SiCl_4 + 4H_2O \rightarrow Si(OH)_4 + 4HCl$. Thus,$Si(OH)_4$ (orthosilici

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(A) The hydrolysis of silicon tetrachloride $(SiCl_4)$ proceeds as follows: $SiCl_4 + 4H_2O \rightarrow Si(OH)_4 + 4HCl$. Thus,$Si(OH)_4$ (orthosilicic acid) is indeed the product formed at the end of the hydrolysis of $SiCl_4$. Therefore,the statement is $True$.