.......... % percent of glucose solution is i | vedclass

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(C) Two solutions are isotonic if they have the same osmotic pressure,i.e.,$\pi_1 = \pi_2$.For solutions with the same temperature and volume,this imp

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$4.5$

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(C) Two solutions are isotonic if they have the same osmotic pressure,i.e.,$\pi_1 = \pi_2$.For solutions with the same temperature and volume,this implies $C_1 = C_2$ or $\frac{n_1}{V} = \frac{n_2}{V}$.Given: Urea solution is $1.5 \% \, (w/V)$,which means $1.5 \, g$ of urea in $100 \, mL$ of solution.Molar mass of urea $(NH_2CONH_2) = 60 \, g/mol$.Molar mass of glucose $(C_6H_{12}O_6) = 180 \, g/mol$.Using the relation $\frac{w_1}{M_1} = \frac{w_2}{M_2}$:$\frac{1.5}{60} = \frac{w_2}{180}$.$w_2 = \frac{1.5 	imes 180}{60} = 1.5 	imes 3 = 4.5 \, g$.Thus,a $4.5 \% \, (w/V)$ glucose solution is isotonic with $1.5 \% \, (w/V)$ urea solution.

$.......... \%$ percent of glucose solution is isotonic with $1.5 \% \, (w/V)$ urea solution.

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