Explore More

Similar Questions

If the surface area of the reactants increases,then the order of the reaction:

$A$ reaction involving two different reactants:

The rate of reaction between two reactants $A$ and $B$ decreases by a factor of $4$ if the concentration of reactant $B$ is doubled. The order of this reaction with respect to reactant $B$ is

Match List-$I$ with List-$II$:
List-$I$ (Order of Reaction)List-$II$ (Unit of rate constant)
$A$. Zero order$I$. $mol^{-1} L s^{-1}$
$B$. First order$II$. $mol^{-2} L^{2} s^{-1}$
$C$. Second order$III$. $s^{-1}$
$D$. Third order$IV$. $mol L^{-1} s^{-1}$

For a reaction between $A$ and $B$,the order with respect to $A$ is $2$ and the order with respect to $B$ is $3$. If the concentrations of both $A$ and $B$ are doubled,the rate will increase by a factor of:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo