What mass in g of hydrated oxalic acid (H_2C_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For complete neutralization,the number of equivalents of oxalic acid must equal the number of equivalents of $NaOH$.$Equivalents = \frac{w}{Eq. \

Vedclass · Accepted Answer

$1.26$

Vedclass · Answer

(D) For complete neutralization,the number of equivalents of oxalic acid must equal the number of equivalents of $NaOH$.$Equivalents = \frac{w}{Eq. \ wt.} = N 	imes V(L)$For hydrated oxalic acid $(H_2C_2O_4 \cdot 2H_2O)$,the molar mass is $126 \ g/mol$ and the $n$-factor is $2$,so the equivalent weight is $\frac{126}{2} = 63 \ g/eq$.Given $V = 100 \ mL = 0.1 \ L$ and $N = 0.2 \ N$.$\frac{w}{63} = 0.2 	imes 0.1$$\frac{w}{63} = 0.02$$w = 0.02 	imes 63 = 1.26 \ g$.Thus,the correct option is $(D)$.

What mass in $g$ of hydrated oxalic acid $(H_2C_2O_4 \cdot 2H_2O)$ should be added for complete neutralization of $100 \ mL$ of $0.2 \ N \ NaOH$ solution?

Similar Questions

The amount of carbon dioxide evolved upon complete combustion of $116 \ g$ of $n$-butane is
(Given : atomic mass in amu $H = 1, C = 12$ and $O = 16$) (in $g$)

What quantity of oxygen is required for complete burning of $15.6 \ g$ benzene (in $g$)?

How many grams of bromine are required to react with $21 \ g$ of $C_3H_6$? (Atomic mass of $Br = 80$)

How many moles of $H_2O_2$ are required for the decolorization of $1$ mole of $KMnO_4$?

The volume of oxygen at $STP$ required to burn $2.4 \,g$ of carbon completely is $.... \,L$

Vedclass Test Series

Exam Paper Generator

Online Exam Module