Predict the product of the following reaction | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction is an oxymercuration-demercuration process. Step $1$: Oxymercuration involves the electrophilic attack of $Hg(OAc)^+$ on the double b

Vedclass · Accepted Answer

$CH_3-CH(OH)-CH_2D$

Vedclass · Answer

(C) The reaction is an oxymercuration-demercuration process. Step $1$: Oxymercuration involves the electrophilic attack of $Hg(OAc)^+$ on the double bond of propene $(CH_3-CH=CH_2)$,followed by the attack of water $(H_2O)$ to form a mercurial alcohol. The $OH$ group attaches to the more substituted carbon (Markovnikov addition),resulting in $CH_3-CH(OH)-CH_2-HgOAc$. Step $2$: Demercuration with $NaBD_4$ replaces the $-HgOAc$ group with a deuterium atom $(D)$. Therefore,the final product is $CH_3-CH(OH)-CH_2D$.

Predict the product of the following reaction: $CH_3-CH=CH_2 \xrightarrow[(2) NaBD_4]{(1) H_2O, Hg(OCOCH_3)_2} \text{Product}$

Similar Questions

What is hydrogenation reaction?

Identify the major product $X$ in the following dehydration reaction: $(CH_3)_3C-CH(OH)-CH_3 \xrightarrow{H_2SO_4} X$.

Baeyer's reagent is ....

How many propenyl radicals are possible from propene?

$A$ hydrocarbon $X$ adds one mole of hydrogen to give another hydrocarbon and decolourises bromine water. $X$ reacts with $KMnO_4$ in the presence of acid to give two moles of the same carboxylic acid. The structure of $X$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module