Two dominant non-allelic genes are 50 map uni | vedclass

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(D) The distance between two genes is measured in map units or centimorgans $(cM)$. $1$ map unit corresponds to $1\%$ recombination frequency. If two

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(D) The distance between two genes is measured in map units or centimorgans $(cM)$. $1$ map unit corresponds to $1\%$ recombination frequency. If two genes are $50$ map units apart,the recombination frequency between them is $50\%$. According to the principle of linkage,if the recombination frequency is $50\%$,the genes behave as if they are assorting independently. Therefore,linkage is considered to be absent or effectively incomplete to the point of independent assortment.

Two dominant non-allelic genes are $50$ map units apart. The linkage present is:

Similar Questions

Briefly mention the contribution of $T.H.$ Morgan in genetics.

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