There are three genes a, b, and c. The percen | vedclass

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(A) The percentage of crossing over is directly proportional to the distance between genes on a chromosome. Therefore,$1\% 	ext{ crossing over} = 1 \

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$b- a- c$

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(A) The percentage of crossing over is directly proportional to the distance between genes on a chromosome. Therefore,$1\% 	ext{ crossing over} = 1 	ext{ map unit (cM)}$.Given distances:$a-b = 20 	ext{ units}$$b-c = 28 	ext{ units}$$a-c = 8 	ext{ units}$To find the sequence,we look for the two smallest distances that add up to the largest distance:$a-c (8) + a-b (20) = 28 	ext{ units} = b-c$.This indicates that gene $a$ lies between $b$ and $c$.Thus,the sequence is $b- a- c$ or $c- a- b$.

There are three genes $a, b,$ and $c$. The percentage of crossing over between $a$ and $b$ is $20\%$,between $b$ and $c$ is $28\%$,and between $a$ and $c$ is $8\%$. What is the sequence of these genes on the chromosome?

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The distance between two linked genes on a chromosome is measured in cross-over units,which is:

. . . . . . $(B)$ . . . . . . used the frequency of recombination between gene pairs on the . . . . . . $(A)$ . . . . . . as a measure of the distance between genes and mapped their position on the chromosome.
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The recombination frequency between the genes $a$ and $c$ is $5\%$,$b$ and $c$ is $15\%$,$b$ and $d$ is $9\%$,$a$ and $b$ is $20\%$,$c$ and $d$ is $24\%$,and $a$ and $d$ is $29\%$. What will be the sequence of these genes on a linear chromosome?

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