A color-blind man marries a woman with normal | vedclass

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(C) Color blindness is an $X$-linked recessive trait. Let $X^c$ represent the color-blind allele and $X$ represent the normal allele.$1$. The man is c

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$0.25$

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(C) Color blindness is an $X$-linked recessive trait. Let $X^c$ represent the color-blind allele and $X$ represent the normal allele.$1$. The man is color-blind $(X^c Y)$. The woman is normal and has no family history,so she is homozygous normal $(XX)$.$2$. Their offspring: The daughter receives $X^c$ from her father and $X$ from her mother,making her a carrier $(X X^c)$. The son receives $Y$ from his father and $X$ from his mother,making him normal $(XY)$.$3$. The daughter (carrier $X X^c$) marries a normal man $(XY)$.$4$. Their children's genotypes: $XX$ (normal daughter),$X X^c$ (carrier daughter),$XY$ (normal son),$X^c Y$ (color-blind son).$5$. The probability of a grandson being color-blind is $0.5$ (since $X^c Y$ is one of two possibilities for a son),and the probability of a granddaughter being color-blind is $0$ (since she must inherit $X^c$ from her father,who is normal). $6$. The question asks for the probability of the daughter's children being color-blind. Since the daughter has a $1/4$ chance of having a color-blind son and $0$ chance of a color-blind daughter,the overall probability for any child is $0.25$.

$A$ color-blind man marries a woman with normal vision,whose family has no history of color blindness. What is the probability that their daughter's children (grandsons and granddaughters) will be color-blind?

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