The number of possible alternative bases in t | vedclass

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(B) The genetic code is a triplet code,meaning each codon consists of $3$ nucleotides. There are $4$ types of nitrogenous bases $(A, U, G, C)$. The to

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$61$

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(B) The genetic code is a triplet code,meaning each codon consists of $3$ nucleotides. There are $4$ types of nitrogenous bases $(A, U, G, C)$. The total number of possible codons is calculated as $4^3 = 4 	imes 4 	imes 4 = 64$. Out of these $64$ codons,$61$ codons code for amino acids,while $3$ codons $(UAA, UAG, UGA)$ are stop codons (nonsense codons) that do not code for any amino acid. Therefore,the number of codons that code for amino acids is $61$.

The number of possible alternative bases in the codons of amino acids is . . . . . . .

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