Me-C equiv C-CH_2-COCl xrightarrow{H_2/Pd-C} | vedclass

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(D) The reaction involves the hydrogenation of an alkyne using $H_2/Pd-C$ (Lindlar's catalyst is not specified,so complete hydrogenation to an alkane

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(D) The reaction involves the hydrogenation of an alkyne using $H_2/Pd-C$ (Lindlar's catalyst is not specified,so complete hydrogenation to an alkane is expected,but typically $Pd-C$ reduces alkynes to alkenes or alkanes depending on conditions. However,$Pd-C$ is a standard catalyst for the reduction of alkynes to alkanes. Given the options,it appears to be a partial reduction to an alkene. The $COCl$ group is generally resistant to reduction by $H_2/Pd-C$ under mild conditions. Therefore,the alkyne $Me-C \equiv C-CH_2-COCl$ is reduced to the corresponding alkene $Me-CH=CH-CH_2-COCl$.

$Me-C \equiv C-CH_2-COCl \xrightarrow{H_2/Pd-C} ?$

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