KOOC-CH_2-CH_2-COOK xrightarrow{text{electrol | vedclass

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Question

(B) The electrolysis of an aqueous solution of potassium succinate is known as $Kolbe's$ electrolysis. During this process,the dicarboxylate ion under

Vedclass · Accepted Answer

$CH_2=CH_2$

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(B) The electrolysis of an aqueous solution of potassium succinate is known as $Kolbe's$ electrolysis. During this process,the dicarboxylate ion undergoes decarboxylation at the anode to form an alkene. The reaction is: $KOOC-CH_2-CH_2-COOK + 2H_2O \xrightarrow{	ext{electrolysis}} CH_2=CH_2 + 2CO_2 + H_2 + 2KOH$. Thus,the major product $(A)$ is ethene $(CH_2=CH_2)$.

$KOOC-CH_2-CH_2-COOK \xrightarrow{\text{electrolysis}} (A) (\text{major})$. Product $(A)$ is:

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