Na_2B_4O_7 cdot 10H_2O xrightarrow{Delta} X + | vedclass

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(C) The thermal decomposition of borax $(Na_2B_4O_7 \cdot 10H_2O)$ yields sodium metaborate $(NaBO_2)$ and boron trioxide $(B_2O_3)$.Thus,$X = B_2O_3$

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$B_2O_3, Cr(BO_2)_3$

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(C) The thermal decomposition of borax $(Na_2B_4O_7 \cdot 10H_2O)$ yields sodium metaborate $(NaBO_2)$ and boron trioxide $(B_2O_3)$.Thus,$X = B_2O_3$.The reaction of $B_2O_3$ with chromium$(III)$ oxide $(Cr_2O_3)$ produces chromium$(III)$ metaborate $(Cr(BO_2)_3)$,which is a green-colored bead.Thus,$Y = Cr(BO_2)_3$.The balanced chemical equations are:$Na_2B_4O_7 \cdot 10H_2O \xrightarrow{\Delta} Na_2B_4O_7 + 10H_2O$$Na_2B_4O_7 \xrightarrow{\Delta} 2NaBO_2 + B_2O_3$$3B_2O_3 + Cr_2O_3 \xrightarrow{\Delta} 2Cr(BO_2)_3$

$Na_2B_4O_7 \cdot 10H_2O \xrightarrow{\Delta} X + NaBO_2 + H_2O$
$X + Cr_2O_3 \xrightarrow{\Delta} Y$ (Green coloured)
$X$ and $Y$ are

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$Na_2B_4O_7 \cdot 10H_2O \xrightarrow{\Delta} X + NaBO_2 + H_2O$$X + Cr_2O_3 \xrightarrow{\Delta} Y$ (Green coloured)$X$ and $Y$ are