$A + H_2O \to B + HCl$
$B + H_2O \to C + HCl$
Compound $(A), (B)$ and $(C)$ will be respectively
$B + H_2O \to C + HCl$
Compound $(A), (B)$ and $(C)$ will be respectively
- A$PCl_5, POCl_3, H_3PO_3$
- B$PCl_5, POCl_3, H_3PO_4$
- C$SOCl_2, POCl_3, H_3PO_3$
- D$PCl_3, POCl_3, H_3PO_4$
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Similar Questions
The basic character of hydrides of the $V$-group elements decreases in the order:
MediumAIPMT 1996
View SolutionWhat are the boiling and freezing points of nitrogen gas?
Medium
View SolutionUnder which conditions can active nitrogen be obtained from $N_2$ gas using an electric spark?
Easy
View SolutionThe compound$(s)$ which generate$(s)$ $N_2$ gas upon thermal decomposition below $300^{\circ} C$ is (are)
$A. NH_4NO_3$
$B. (NH_4)_2Cr_2O_7$
$C. Ba(N_3)_2$
$D. Mg_3N_2$
$A. NH_4NO_3$
$B. (NH_4)_2Cr_2O_7$
$C. Ba(N_3)_2$
$D. Mg_3N_2$
MediumIIT 2018
View SolutionIdentify the correct orders from the following with respect to the property associated with:
$A$. $NH_3 > PH_3 > AsH_3 > SbH_3$ - Bond Angle
$B$. $NH_3 > PH_3 > AsH_3 > SbH_3$ - Basic Character
$C$. $PH_3 > AsH_3 > SbH_3 > NH_3$ - Thermal stability
$D$. $SbH_3 > NH_3 > AsH_3 > PH_3$ - Boiling point
$A$. $NH_3 > PH_3 > AsH_3 > SbH_3$ - Bond Angle
$B$. $NH_3 > PH_3 > AsH_3 > SbH_3$ - Basic Character
$C$. $PH_3 > AsH_3 > SbH_3 > NH_3$ - Thermal stability
$D$. $SbH_3 > NH_3 > AsH_3 > PH_3$ - Boiling point
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