Given A = 2 hat{i} + hat{j},B = 3 hat{j} - ha | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given vectors are $A = 2 \hat{i} + \hat{j}$,$B = 3 \hat{j} - \hat{k}$,and $C = 6 \hat{i} - 2 \hat{k}$.We need to calculate $A - 2B + 3C$.Substitut

Vedclass · Accepted Answer

$20 \hat{i} - 5 \hat{j} - 4 \hat{k}$

Vedclass · Answer

(B) Given vectors are $A = 2 \hat{i} + \hat{j}$,$B = 3 \hat{j} - \hat{k}$,and $C = 6 \hat{i} - 2 \hat{k}$.We need to calculate $A - 2B + 3C$.Substitute the given vectors into the expression:$A - 2B + 3C = (2 \hat{i} + \hat{j}) - 2(3 \hat{j} - \hat{k}) + 3(6 \hat{i} - 2 \hat{k})$Expand the terms:$= 2 \hat{i} + \hat{j} - 6 \hat{j} + 2 \hat{k} + 18 \hat{i} - 6 \hat{k}$Group the components of $\hat{i}$,$\hat{j}$,and $\hat{k}$:$= (2 + 18) \hat{i} + (1 - 6) \hat{j} + (2 - 6) \hat{k}$$= 20 \hat{i} - 5 \hat{j} - 4 \hat{k}$

Given $A = 2 \hat{i} + \hat{j}$,$B = 3 \hat{j} - \hat{k}$,and $C = 6 \hat{i} - 2 \hat{k}$. The value of $A - 2B + 3C$ is:

Similar Questions

The magnitudes of two vectors are $8$ units and $6$ units respectively. Find the magnitude of the resultant vector if the angle between these two vectors is $(i) \theta = 0^{\circ}$,$(ii) \theta = 180^{\circ}$,$(iii) \theta = 90^{\circ}$,and $(iv) \theta = 120^{\circ}$.

If $\vec{A} + \vec{B} = \vec{C}$ and $A + B = C$,what is the angle between $\vec{A}$ and $\vec{B}$?

There are five vectors,each of magnitude $8$ units. These vectors form a regular pentagon as shown in the figure. Find the magnitude of the resultant vector.

Explain the subtraction of vectors.

Two forces,each numerically equal to $10$ $dyne$,are acting as shown in the adjoining figure. The magnitude of the resultant force is ......... $dyne$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module