19.7 kg of gold was recovered from a smuggle | vedclass

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(D) Given mass of gold $= 19.7 \ kg = 19700 \ g$.Atomic mass of gold $(Au)$ $= 197 \ g/mol$.Number of moles of gold $= \frac{	ext{Given mass}}{	ext{

Vedclass · Accepted Answer

$6.02 	imes 10^{25}$

Vedclass · Answer

(D) Given mass of gold $= 19.7 \ kg = 19700 \ g$.Atomic mass of gold $(Au)$ $= 197 \ g/mol$.Number of moles of gold $= \frac{	ext{Given mass}}{	ext{Atomic mass}} = \frac{19700 \ g}{197 \ g/mol} = 100 \ mol$.Number of atoms $= 	ext{Number of moles} 	imes 	ext{Avogadro's number} (N_A)$.Number of atoms $= 100 	imes 6.022 	imes 10^{23} = 6.022 	imes 10^{25} 	ext{ atoms}$.Thus,the correct option is $(D)$.

$19.7 \ kg$ of gold was recovered from a smuggler. How many atoms of gold were recovered? (Atomic mass of $Au = 197 \ g/mol$)

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