2 g of oxygen contains a number of atoms equ | vedclass

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(B) The number of moles of atoms in $2 \ g$ of oxygen $(O)$ is calculated as: $	ext{Moles of } O = \frac{	ext{mass}}{	ext{atomic mass}} = \frac{2 \

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$4 \ g$ of sulphur

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(B) The number of moles of atoms in $2 \ g$ of oxygen $(O)$ is calculated as: $	ext{Moles of } O = \frac{	ext{mass}}{	ext{atomic mass}} = \frac{2 \ g}{16 \ g/mol} = 0.125 \ mol = \frac{1}{8} \ mol$.Now,let us calculate the moles of atoms for each option:$A) \ 0.5 \ g$ of hydrogen $(H)$: $	ext{Moles} = \frac{0.5}{1} = 0.5 \ mol$.$B) \ 4 \ g$ of sulphur $(S)$: $	ext{Moles} = \frac{4}{32} = 0.125 \ mol = \frac{1}{8} \ mol$.$C) \ 7 \ g$ of nitrogen $(N)$: $	ext{Moles} = \frac{7}{14} = 0.5 \ mol$.$D) \ 2.3 \ g$ of sodium $(Na)$: $	ext{Moles} = \frac{2.3}{23} = 0.1 \ mol$.Since $4 \ g$ of sulphur contains the same number of moles of atoms as $2 \ g$ of oxygen,the correct option is $B$.

$2 \ g$ of oxygen contains a number of atoms equal to that in:

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