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(D) The terminal potential difference $V$ is given by the equation $V = E_{eq} - I r_{eq}$.From the graph,the intercept on the $V$-axis is $E_{eq}$ an

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$4.2$

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(D) The terminal potential difference $V$ is given by the equation $V = E_{eq} - I r_{eq}$.From the graph,the intercept on the $V$-axis is $E_{eq}$ and the intercept on the $I$-axis is $I_{sc} = E_{eq} / r_{eq}$.Using the slope of the line:Slope $= -r_{eq} = \frac{6 - 0}{12 - 14} = \frac{6}{-2} = -3 \, \Omega$.Thus,$r_{eq} = 3 \, \Omega$.At $I = 12 \, A$,$V = 6 \, V$.Using $V = E_{eq} - I r_{eq}$:$6 = E_{eq} - (12)(3)$$6 = E_{eq} - 36$$E_{eq} = 42 \, V$.Since $10$ cells are connected in series,$E_{eq} = 10 E$.$10 E = 42 \, V$$E = 4.2 \, V$.

List-$I$	List-$II$
$(A)$ $P(E_2)$	$(i)$ $1/4$
$(B)$ $P(E_1 \cup E_2)$	$(ii)$ $5/8$
$(C)$ $P(\bar{E}_1 / \bar{E}_2)$	$(iii)$ $1/8$
$(D)$ $P(E_1 / \bar{E}_2)$	$(iv)$ $1/2$
	$(v)$ $3/8$
	$(vi)$ $3/4$

$10$ cells,each of emf $E$ and internal resistance $r$,are connected in series to a variable external resistance. The figure shows the variation of the terminal potential difference of their combination with the current drawn from the combination. The emf of each cell is ............. $V$.

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