Ph-COOH + C_2H_5-^{18}OH xrightarrow{Conc. H_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In the Fischer esterification reaction between a carboxylic acid and an alcohol,the $OH$ group is removed from the carboxylic acid and the $H$ ato

Vedclass · Accepted Answer

$Ph-C(=O)-^{18}O-C_2H_5$

Vedclass · Answer

(D) In the Fischer esterification reaction between a carboxylic acid and an alcohol,the $OH$ group is removed from the carboxylic acid and the $H$ atom is removed from the alcohol to form water $(H_2O)$.Therefore,the oxygen atom from the alcohol $(^{18}O)$ is incorporated into the ester linkage.The reaction is: $Ph-COOH + C_2H_5-^{18}OH \xrightarrow{H^+} Ph-C(=O)-^{18}O-C_2H_5 + H_2O$.Thus,the correct option is $D$.

$Ph-COOH + C_2H_5-^{18}OH \xrightarrow{Conc. H_2SO_4} \text{Major product will be}$

Similar Questions

Given below are two statements :
Statement $I :$ The esterification of carboxylic acid with an alcohol is a nucleophilic acyl substitution.
Statement $II :$ Electron withdrawing groups in the carboxylic acid will increase the rate of esterification reaction.
Choose the most appropriate option

Which of the following acids will have the lowest dissociation constant $(K_a)$?

In the ring substitution reaction of $C_6H_5Y$,the major product obtained is the $m-$ isomer. What is the group $Y$?

Aspirin is an acetylation product of

Which of the following is most acidic?

Vedclass Test Series

Exam Paper Generator

Online Exam Module