[Fe(N_3)(O_2)(SCN)_4]^{4-} is named as | vedclass

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Question

(A) The oxidation state of $Fe$ is calculated as: $x + (-1) + (-1) + 4(-1) = -4$,which gives $x = +2$. The ligands present are: $N_3^-$ (azido),$O_2^-

Vedclass · Accepted Answer

azidosuperoxidotetrathiocyanato-$S$-ferrate$(II)$

Vedclass · Answer

(A) The oxidation state of $Fe$ is calculated as: $x + (-1) + (-1) + 4(-1) = -4$,which gives $x = +2$. The ligands present are: $N_3^-$ (azido),$O_2^-$ (superoxido),and $SCN^-$ (thiocyanato-$S$). Since the complex ion is anionic,the metal name ends in '-ate',hence 'ferrate$(II)$'. Combining these,the $IUPAC$ name is azidosuperoxidotetrathiocyanato-$S$-ferrate$(II)$.

$[Fe(N_3)(O_2)(SCN)_4]^{4-}$ is named as

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