S_1 and S_2 are two equipotential surfaces on | vedclass

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(B) $1$. Two equipotential surfaces can never intersect because if they did,the point of intersection would have two different potential values,which

Vedclass · Accepted Answer

$S_1$ and $S_2$ cannot be plane surfaces.

Vedclass · Answer

(B) $1$. Two equipotential surfaces can never intersect because if they did,the point of intersection would have two different potential values,which is physically impossible.$2$. Equipotential surfaces can indeed be plane surfaces (e.g.,for a uniform electric field). Therefore,the statement that they cannot be plane surfaces is incorrect.$3$. The relationship between the electric field $E$ and potential $V$ is given by $E = -dV/dx$. This implies that for a fixed potential difference $dV$,the electric field $E$ is inversely proportional to the distance $dx$ between the surfaces. Thus,where the surfaces are closest,the electric field is maximum.$4$. By definition,electric field lines (lines of force) are always perpendicular to equipotential surfaces.$5$. Since statement $(B)$ is the only incorrect statement,it is the correct choice.

$S_1$ and $S_2$ are two equipotential surfaces on which the potentials are not equal. Which of the following statements is incorrect?

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