B_2H_6 + 2NaH to compound P. Identify the hyb | vedclass

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Question

(B) The reaction between diborane $(B_2H_6)$ and sodium hydride $(NaH)$ in an ether solvent yields sodium borohydride $(NaBH_4)$: $B_2H_6 + 2NaH 	o 2

Vedclass · Accepted Answer

$sp^3$

Vedclass · Answer

(B) The reaction between diborane $(B_2H_6)$ and sodium hydride $(NaH)$ in an ether solvent yields sodium borohydride $(NaBH_4)$: $B_2H_6 + 2NaH 	o 2NaBH_4$. In the borohydride ion $([BH_4]^-)$,the Boron atom is bonded to four Hydrogen atoms via single covalent bonds. Since the Boron atom has a steric number of $4$ (four sigma bonds and zero lone pairs),its hybridisation is $sp^3$.

$B_2H_6 + 2NaH \to$ compound $P$. Identify the hybridisation of Boron in compound $P$.

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