$CH_3-CH=CH_2 + NOCl \to$ Product (Major). Identify the product.

Consider compounds $A$, $B$, and $C$ with the following structural formulae:
$A = CH_3 - CH_2 - CH_2 - CH_2 - CH_2 - OH$
$B = CH_2 = CH - CH_2 - CH_2 - CH_3$
$C = HO - CH_2 - CH_2 - CH(OH) - CH_3$
For the conversion of $B$ from $A$, the reagent $(D)$ required is . . . . . . and the structural formula of the product $(E)$ obtained when $C$ undergoes the same reaction using excess reagent $(D)$ is . . . . . . .

Reaction of $tert.-$butyl alcohol with hot $Cu$ at $350 \, ^oC$ produces

$\underset{C_7H_{14}}{(A)} \xrightarrow[Zn/AcOH]{O_3} (B) + (C)$
Compound $(A)$ exists as geometrical isomers and $(B)$ gives the Cannizzaro reaction. $(A)$ will be:

Identify the major product $B$ in the given sequence of reactions:
$CH_3-C \equiv CH$ $\xrightarrow{H_2 / Pd-C} A$ $\xrightarrow{(C_6H_5CO)_2O_2 / HBr} B$

Isobutene,in the presence of $H_2SO_4$,forms a mixture of two isomeric alkenes $(C_8H_{16})$. The major alkene is