$6.02 \times 10^{20}$ molecules of urea are present in $200 \ mL$ of its solution. The concentration of urea solution is .............. $M$
- A$0.001$
- B$0.01$
- C$0.005$
- D$0.10$
Explore More
Similar Questions
Choose the correct option for the mole fraction of both components in a gaseous mixture containing $7 \ g$ of nitrogen and $8 \ g$ of oxygen.
Easy
View SolutionWhat is the molarity of $H_2O$ in pure water?
Medium
View SolutionWhich of the following relations is incorrect?
Difficult
View SolutionWhich of the following contains the maximum number of atoms?
Medium
View SolutionMatch List-$I$ with List-$II$. List-$I$ (Mass of substance) List-$II$ (Number of atoms) $A$. $1.8 \text{ mg}$ water $I$. $2 \times 10^{-4} \times N_{A}$ $B$. $9.8 \text{ mg}$ sulphuric acid $II$. $1.5 \times 10^{-4} \times N_{A}$ $C$. $1.8 \text{ mg}$ carbon $III$. $3 \times 10^{-4} \times N_{A}$ $D$. $5.85 \text{ mg}$ salt (NaCl) $IV$. $7 \times 10^{-4} \times N_{A}$
| List-$I$ (Mass of substance) | List-$II$ (Number of atoms) |
| $A$. $1.8 \text{ mg}$ water | $I$. $2 \times 10^{-4} \times N_{A}$ |
| $B$. $9.8 \text{ mg}$ sulphuric acid | $II$. $1.5 \times 10^{-4} \times N_{A}$ |
| $C$. $1.8 \text{ mg}$ carbon | $III$. $3 \times 10^{-4} \times N_{A}$ |
| $D$. $5.85 \text{ mg}$ salt (NaCl) | $IV$. $7 \times 10^{-4} \times N_{A}$ |
DifficultJEE MAIN 2026
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo