In the reaction sequence: C_6H_5NH_2 xrightar | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction sequence is as follows:$1$. Aniline $(C_6H_5NH_2)$ reacts with chloroform $(CHCl_3)$ and alcoholic potassium hydroxide $(KOH)$ under

Vedclass · Accepted Answer

$C_6H_5NHCH_3$

Vedclass · Answer

(A) The reaction sequence is as follows:$1$. Aniline $(C_6H_5NH_2)$ reacts with chloroform $(CHCl_3)$ and alcoholic potassium hydroxide $(KOH)$ under heating to undergo the carbylamine reaction,forming phenyl isocyanide $(C_6H_5NC)$ as product $(X)$.$C_6H_5NH_2 + CHCl_3 + 3KOH \xrightarrow{\Delta} C_6H_5NC + 3KCl + 3H_2O$$2$. Phenyl isocyanide $(C_6H_5NC)$ is then reduced using lithium aluminium hydride $(LiAlH_4)$ followed by hydrolysis to yield $N$-methylaniline $(C_6H_5NHCH_3)$ as product $(Y)$.$C_6H_5NC \xrightarrow{LiAlH_4/H_2O} C_6H_5NHCH_3$Therefore,the correct option is $(A)$.

In the reaction sequence: $C_6H_5NH_2$ $\xrightarrow{CHCl_3/KOH, \Delta} (X)$ $\xrightarrow{LiAlH_4/H_2O} (Y)$,the product $(Y)$ is:

Similar Questions

Explain the basicity of aliphatic amines.

The order of basicity among the following compounds is:

Consider the following reaction:
$C_6H_5NO_2$ $\xrightarrow{Sn/HCl} X$ $\xrightarrow{C_6H_5COCl} Y + HCl$
What is $Y$?

Explain the chemical reactions of benzene-diazonium chloride.

Which of the following sets of reagents convert aniline to chlorobenzene?

Vedclass Test Series

Exam Paper Generator

Online Exam Module