5 , L of a gaseous mixture of ethane and prop | vedclass

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(C) Let the volume of $C_2H_6$ be $x \, L$ and the volume of $C_3H_8$ be $(5-x) \, L$.The combustion reactions are:$C_2H_6 + \frac{7}{2}O_2 	o 2CO_2

Vedclass · Accepted Answer

$80$

Vedclass · Answer

(C) Let the volume of $C_2H_6$ be $x \, L$ and the volume of $C_3H_8$ be $(5-x) \, L$.The combustion reactions are:$C_2H_6 + \frac{7}{2}O_2 	o 2CO_2 + 3H_2O$$C_3H_8 + 5O_2 	o 3CO_2 + 4H_2O$From the stoichiometry,$x \, L$ of $C_2H_6$ produces $2x \, L$ of $CO_2$.$(5-x) \, L$ of $C_3H_8$ produces $3(5-x) \, L$ of $CO_2$.Total volume of $CO_2$ produced is $11 \, L$:$2x + 3(5-x) = 11$$2x + 15 - 3x = 11$$-x = -4$$x = 4 \, L$Volume percentage of $C_2H_6 = \frac{	ext{Volume of } C_2H_6}{	ext{Total volume}} 	imes 100 = \frac{4}{5} 	imes 100 = 80 \%$.

$5 \, L$ of a gaseous mixture of ethane and propane are burnt to produce total $11 \, L$ of $CO_2$. Volume percent of $C_2H_6$ in the initial mixture is

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