The reaction of $1,3$-butadiene with $1$ equivalent of $HBr$ at different temperatures yields products $A$ and $B$. Identify the relationship between $A$ and $B$. The reaction scheme is as follows:
$CH_2=CH-CH=CH_2 + HBr (1 \text{ eq}) \xrightarrow{25^{\circ}C} A$
$CH_2=CH-CH=CH_2 + HBr (1 \text{ eq}) \xrightarrow{-80^{\circ}C} B$

  • A
    Chain isomers
  • B
    Position isomers
  • C
    Identical
  • D
    Geometrical isomers

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The product $(P)$ is:

Given below are two statements.
Statement $I :$ The presence of weaker $\pi$-bonds makes alkenes less stable than alkanes.
Statement $II :$ The strength of the double bond is greater than that of carbon-carbon single bond.
In the light of the above statements,choose the correct answer from the options given below.

In the following sequence of reactions,the alkene affords the compound $B$.
$CH_3-CH=CH-CH_3$ $\xrightarrow{O_3} A$ $\xrightarrow[Zn]{H_2O} B$
The compound $B$ is:

The reaction of isobutene with $HBr$ yields:

Which among the following alkenes is most stable?

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