The electronic configuration $4d^3$ $5s^2$ belongs to which group in the periodic table?
- A$II$ $A$
- B$II$ $B$
- C$V$ $B$
- D$III$ $B$
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View SolutionMatch List-$I$ with List-$II$:
List-$I$ ($\text{Transition metal ion}$) List-$II$ ($\text{Spin only magnetic moment (B.M.)}$) $A$. $Ti^{3+}$ $I$. $3.87$ $B$. $V^{2+}$ $II$. $0.00$ $C$. $Ni^{2+}$ $III$. $1.73$ $D$. $Sc^{3+}$ $IV$. $2.84$
Choose the correct answer from the options given below:
| List-$I$ ($\text{Transition metal ion}$) | List-$II$ ($\text{Spin only magnetic moment (B.M.)}$) |
|---|---|
| $A$. $Ti^{3+}$ | $I$. $3.87$ |
| $B$. $V^{2+}$ | $II$. $0.00$ |
| $C$. $Ni^{2+}$ | $III$. $1.73$ |
| $D$. $Sc^{3+}$ | $IV$. $2.84$ |
Choose the correct answer from the options given below:
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