$6 Fe_3O_4 + 2 MnO_4^- + H_2O \to 9 Fe_2O_3 + 2 MnO_2 + 2 OH^-$ Calculate the equivalent weight of $Fe_3O_4$ in the above equation.

In alkaline medium,what will be the equivalent weight of $I_2$ on its conversion to iodate ion $(IO_3^-)$?

The number of moles of acidified $KMnO_4$ required to convert one mole of sulphite ion into sulphate ion is

$2 IO_3^- + x I^- + 12 H^+ \rightarrow 6 I_2 + 6 H_2 O$. What is the value of $x$?

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$Pb_3O_4 + 8HCl \xrightarrow{\text{Warm}} 3PbCl_2 + Cl_2 + 4H_2O$

In neutral or faintly alkaline medium,$KMnO_4$ being a powerful oxidant can oxidize thiosulphate almost quantitatively to sulphate. In this reaction,the overall change in the oxidation state of manganese will be: