EAN of Fe in [Fe(C_2O_4)_3]^{3-} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $E.A.N. = 	ext{Atomic number of central metal ion} - 	ext{Oxidation number of central metal ion} + 2 	imes 	ext{Coordination number of central

Vedclass · Accepted Answer

$35$

Vedclass · Answer

(C) $E.A.N. = 	ext{Atomic number of central metal ion} - 	ext{Oxidation number of central metal ion} + 2 	imes 	ext{Coordination number of central metal ion.}$ Atomic number of $Fe = 26$. Oxidation number of $Fe$ in $[Fe(C_2O_4)_3]^{3-}$ is calculated as: $x + 3(-2) = -3 \implies x = +3$. Coordination number of $Fe$ with bidentate ligand $C_2O_4^{2-}$ is $3 	imes 2 = 6$. $E.A.N. = 26 - 3 + 2 	imes 6 = 23 + 12 = 35$. Hence,option $C$ is correct.

$EAN$ of $Fe$ in $[Fe(C_2O_4)_3]^{3-}$

Similar Questions

What is the Effective Atomic Number $(EAN)$ of the metal ion in $[Cu(NH_3)_4]^{2+}$?

The effective atomic number of Iron $(Z = 26)$ in $[Fe(CN)_6]^{3-}$ is

$EAN$ of complex $[Fe(C_2O_4)_3]^{3-}$ is

In $K_4[Fe(CN)_6]$,the $E.A.N.$ of $Fe$ is

In $[Ni(NH_3)_4]SO_4$,the $E.A.N.$ of $Ni$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module