CH_3-CH=O (I) rightleftharpoons CH_2=CH-OH (I | vedclass

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(A) The stability of tautomers is determined by the bond energies of the functional groups involved.In structure $(I)$,the $C=O$ bond is present,while

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$I$

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(A) The stability of tautomers is determined by the bond energies of the functional groups involved.In structure $(I)$,the $C=O$ bond is present,while in structure $(II)$,the $C=C$ bond and $O-H$ bond are present.The bond energy of the $C=O$ bond (approx. $745 \ kJ/mol$) is significantly higher than the sum of the bond energies of the $C=C$ bond (approx. $610 \ kJ/mol$) and the $O-H$ bond (approx. $460 \ kJ/mol$) when considering the overall enthalpy of the system.Therefore,the keto form $(I)$ is more stable than the enol form $(II)$.

$CH_3-CH=O$ $(I)$ $\rightleftharpoons$ $CH_2=CH-OH$ $(II)$
Between the two tautomers,which is more stable?

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$CH_3-CH=O$ $(I)$ $\rightleftharpoons$ $CH_2=CH-OH$ $(II)$Between the two tautomers,which is more stable?