For the compound CH_3-CH=CH-CH=CH-CH_3,the to | vedclass

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(B) The given compound is a symmetrical polyene with two double bonds capable of showing geometrical isomerism.For a symmetrical polyene with $n$ doub

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$3$

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(B) The given compound is a symmetrical polyene with two double bonds capable of showing geometrical isomerism.For a symmetrical polyene with $n$ double bonds,the number of geometrical isomers is given by the formula:If $n$ is even,$N = 2^{n-1} + 2^{(n/2)-1}$.Here,$n = 2$,so $N = 2^{2-1} + 2^{(2/2)-1} = 2^1 + 2^0 = 2 + 1 = 3$.The three isomers are $ZZ$,$EE$,and $ZE$ (or $EZ$,which is identical to $ZE$ due to symmetry).

For the compound $CH_3-CH=CH-CH=CH-CH_3$,the total number of geometrical isomers is:

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