The same product (A) is formed in both of the | vedclass

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(C) In reaction $1.$,the Grignard reagent $(PhMgBr)$ adds to the nitrile $(CH_3-CN)$ to form an imine salt,which upon acidic hydrolysis $(H_3O^{+})$ y

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$Ph-C(=O)-CH_3$

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(C) In reaction $1.$,the Grignard reagent $(PhMgBr)$ adds to the nitrile $(CH_3-CN)$ to form an imine salt,which upon acidic hydrolysis $(H_3O^{+})$ yields acetophenone $(Ph-C(=O)-CH_3)$. In reaction $2.$,the carboxylic acid $(Ph-COOH)$ reacts with two equivalents of organolithium $(CH_3Li)$ to form a gem-dialkoxide intermediate,which upon acidic hydrolysis yields acetophenone $(Ph-C(=O)-CH_3)$. Therefore,$(A)$ is acetophenone,which corresponds to option $(C)$.

The same product $(A)$ is formed in both of the following reactions:
$1. PhMgBr + CH_3-CN \xrightarrow{H_3O^{+}} (A)$
$2. Ph-COOH \xrightarrow{(1) \text{ excess } CH_3Li, (2) H_3O^{+}} (A)$
Identify product $(A)$.

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The same product $(A)$ is formed in both of the following reactions: $1. PhMgBr + CH_3-CN \xrightarrow{H_3O^{+}} (A)$ $2. Ph-COOH \xrightarrow{(1) \text{ excess } CH_3Li, (2) H_3O^{+}} (A)$ Identify product $(A)$.