CH_3-C(CH_3)(Br)-CH(CH_3)_2 xrightarrow[Delta | vedclass

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(B) The reaction proceeds via an $E1$ mechanism.$1$. The substrate $CH_3-C(CH_3)(Br)-CH(CH_3)_2$ undergoes ionization to form a secondary carbocation:

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$2,3-$dimethylbut$-2-$ene

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(B) The reaction proceeds via an $E1$ mechanism.$1$. The substrate $CH_3-C(CH_3)(Br)-CH(CH_3)_2$ undergoes ionization to form a secondary carbocation: $CH_3-C^+(CH_3)-CH(CH_3)_2$.$2$. This secondary carbocation undergoes a $1,2-methyl$ shift to form a more stable tertiary carbocation: $(CH_3)_2C^+-CH(CH_3)_2$.$3$. Finally, the loss of a proton $(H^+)$ from the adjacent carbon leads to the formation of the most stable alkene, which is $2,3-dimethylbut-2-ene$ (tetrasubstituted alkene).

$CH_3-C(CH_3)(Br)-CH(CH_3)_2 \xrightarrow[\Delta]{EtOH} (A)$
Major product $(A)$ is

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$CH_3-C(CH_3)(Br)-CH(CH_3)_2 \xrightarrow[\Delta]{EtOH} (A)$Major product $(A)$ is