$\underset{(A)}{C_5H_{10}O} \xrightarrow{H_3O^{\oplus}} B + C$; $(B)$ and $(C)$ both give positive iodoform test. Compound $(A)$ is

  • A
    $CH_3-CH=CH-O-CH_2-CH_3$
  • B
    $CH_3-CH(CH_3)-O-CH_2-CH_3$
  • C
    $CH_3-C(=CH_2)-O-CH_2-CH_3$
  • D
    both $(b)$ and $(c)$

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