$1, 2, 3$-butanetriol undergoes oxidative cleavage with $HIO_4$. During this process:

  • A
    $1$ equivalent of $HIO_4$ is consumed and $HCO_2H$ and $CH_3-C(=O)-CO_2H$ are formed.
  • B
    $2$ equivalents of $HIO_4$ are consumed and $HCO_2H, HCH=O$ and $CH_3-CH=O$ are formed.
  • C
    $3$ equivalents of $HIO_4$ are consumed and $2$ eq. of $HCO_2H$ and $1$ eq. of $CH_3CO_2H$ are formed.
  • D
    $2$ equivalents of $HIO_4$ are consumed and $2$ eq. of $HCO_2H$ and $1$ eq. of $CH_3CH=O$ are formed.

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