Ph-CH_2-Cequiv N xrightarrow[THF]{LDA} xright | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction involves the use of $LDA$ (Lithium Di-isopropylamide),which is a strong,sterically hindered base. $LDA$ abstracts the acidic $\alpha$

Vedclass · Accepted Answer

$Ph-CH(CH_3)-C\equiv N$

Vedclass · Answer

(C) The reaction involves the use of $LDA$ (Lithium Di-isopropylamide),which is a strong,sterically hindered base. $LDA$ abstracts the acidic $\alpha$-hydrogen from the phenylacetonitrile $(Ph-CH_2-C\equiv N)$ to form a resonance-stabilized carbanion: $Ph-CH^--C\equiv N \leftrightarrow Ph-CH=C=N^-$. This carbanion then acts as a nucleophile and attacks the methyl iodide $(CH_3I)$ in an $S_N2$ reaction. The resulting product is $Ph-CH(CH_3)-C\equiv N$.

$Ph-CH_2-C\equiv N$ $\xrightarrow[THF]{LDA}$ $\xrightarrow{CH_3I} 71\%;$ The end product of this reaction will be:

Similar Questions

Product $(C)$ of the above reaction is

The major product $'A'$ of the following given reaction has $......\,sp^2$ hybridized carbon atoms.
$2,7-\text{Dimethyl}-2,6-\text{octadiene} \xrightarrow{H^{+}} A \text{ (Major Product)}$

Total number of isomers (including stereoisomers) obtained on monochlorination of methylcyclohexane is $........$

Write chemical equations for the combustion reaction of the following hydrocarbons:
$(i)$ Pentene
$(ii)$ Hexyne
$(iii)$ Toluene

Arrange the stability of the given gem-diols in decreasing order:
$I$: Cyclopropane$-1,1-$diol
$II$: Cyclobutane$-1,1-$diol
$III$: Cyclopentane$-1,1-$diol

Vedclass Test Series

Exam Paper Generator

Online Exam Module