CH_3CHO xrightarrow[5,^{circ}C]{10%,NaOH} xri | vedclass

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Question

(C) $1$. $CH_3CHO$ in the presence of $10\% \, NaOH$ at $5\,^{\circ}C$ undergoes Aldol condensation to form $3-hydroxybutanal$ $(CH_3-CH(OH)-CH_2-CHO)

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butanol

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(C) $1$. $CH_3CHO$ in the presence of $10\% \, NaOH$ at $5\,^{\circ}C$ undergoes Aldol condensation to form $3-hydroxybutanal$ $(CH_3-CH(OH)-CH_2-CHO)$.$2$. Upon heating $(\Delta)$,$3-hydroxybutanal$ undergoes dehydration to form $but-2-enal$ $(CH_3-CH=CH-CHO)$.$3$. Finally,hydrogenation with $H_2/Ni$ reduces both the aldehyde group and the carbon-carbon double bond to form $n-butanol$ $(CH_3-CH_2-CH_2-CH_2-OH)$.

$CH_3CHO$ $\xrightarrow[5\,^{\circ}C]{10\%\,NaOH}$ $\xrightarrow[\Delta]{}$ $\xrightarrow[Ni]{H_2} (A)$; Product $(A)$ of the reaction is

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