CH_3CH_2CH(OH)CH(CH_3)_2 + CH_3COCl xrightarr | vedclass

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(C) The reaction is an esterification reaction between an alcohol and an acid chloride in the presence of a base.In this reaction,the $O-H$ bond of th

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have the same configuration at the chiral atom

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(C) The reaction is an esterification reaction between an alcohol and an acid chloride in the presence of a base.In this reaction,the $O-H$ bond of the alcohol is broken,and the $C-O$ bond remains intact.Since the chiral center is the carbon atom attached to the oxygen atom $(C-OH)$,and the bond between this carbon and the oxygen is not broken during the reaction,the configuration at the chiral center remains unchanged.Therefore,if the reactant alcohol is a pure $R$-isomer,the product will also have the same $R$-configuration at the chiral center.

$CH_3CH_2CH(OH)CH(CH_3)_2 + CH_3COCl \xrightarrow{\text{base}} CH_3CH_2CH(OCOCH_3)CH(CH_3)_2 + HCl$
In the above reaction,if the reactant alcohol is a pure $R$-isomer,the product would:

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$CH_3CH_2CH(OH)CH(CH_3)_2 + CH_3COCl \xrightarrow{\text{base}} CH_3CH_2CH(OCOCH_3)CH(CH_3)_2 + HCl$In the above reaction,if the reactant alcohol is a pure $R$-isomer,the product would: