$R-CONH_2 + xNaOH + Br_2 \to R-NH_2 + 2NaBr + Na_2CO_3 + H_2O$
The number of moles of $NaOH$ used in the above Hoffmann bromamide reaction is:

  • A
    $3$
  • B
    $4$
  • C
    $5$
  • D
    $6$

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