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(C) The reaction of $C_6H_5-CH_2-CH=CH_2$ with $HCl$ follows electrophilic addition.First,the proton $(H^+)$ from $HCl$ adds to the terminal carbon to

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$C_6H_5-CH(Cl)-CH_2-CH_3$

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(C) The reaction of $C_6H_5-CH_2-CH=CH_2$ with $HCl$ follows electrophilic addition.First,the proton $(H^+)$ from $HCl$ adds to the terminal carbon to form the most stable carbocation.The intermediate formed is a benzylic carbocation,$C_6H_5-CH^+-CH_2-CH_3$,which is highly stable due to resonance with the phenyl ring.Finally,the chloride ion $(Cl^-)$ attacks this carbocation to form the product $X$,which is $C_6H_5-CH(Cl)-CH_2-CH_3$.

What is the product $X$ in the following reaction?
$C_6H_5-CH_2-CH=CH_2 + HCl \rightarrow X$

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What is the product $X$ in the following reaction?$C_6H_5-CH_2-CH=CH_2 + HCl \rightarrow X$