A xrightarrow{4 KOH, O_2} 2 B (Green) + 2 H_2 | vedclass

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(B) The given reactions represent the chemistry of manganese compounds:$1$. $2 MnO_2 + 4 KOH + O_2 \rightarrow 2 K_2MnO_4 (Green) + 2 H_2O$. Thus,$A =

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$MnO_2$ and $KIO_3$

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(B) The given reactions represent the chemistry of manganese compounds:$1$. $2 MnO_2 + 4 KOH + O_2 \rightarrow 2 K_2MnO_4 (Green) + 2 H_2O$. Thus,$A = MnO_2$ and $B = K_2MnO_4$.$2$. $3 K_2MnO_4 + 4 HCl \rightarrow 2 KMnO_4 (Purple) + MnO_2 + 2 H_2O$. Thus,$C = KMnO_4$.$3$. $2 KMnO_4 + H_2O + KI \rightarrow 2 MnO_2 + 2 KOH + KIO_3$. Thus,$D = KIO_3$.Comparing these,$A = MnO_2$ and $D = KIO_3$.

$A \xrightarrow{4 KOH, O_2} 2 B (Green) + 2 H_2O$
$3 B \xrightarrow{4 HCl} 2 C (Purple) + MnO_2 + 2 H_2O$
$3 C \xrightarrow{H_2O, KI} 2 A + 2 KOH + D$
In the above sequence of reactions,$A$ and $D$,respectively,are:

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$A \xrightarrow{4 KOH, O_2} 2 B (Green) + 2 H_2O$$3 B \xrightarrow{4 HCl} 2 C (Purple) + MnO_2 + 2 H_2O$$3 C \xrightarrow{H_2O, KI} 2 A + 2 KOH + D$In the above sequence of reactions,$A$ and $D$,respectively,are: