$\wedge _m^o$ for $NaCl$,$HCl$ and $NaA$ are $126.4$,$425.9$ and $100.5 \ S \ cm^2 \ mol^{-1}$,respectively. If the conductivity of $0.001 \ M \ HA$ is $5 \times 10^{-5} \ S \ cm^{-1}$,degree of dissociation of $HA$ is

If the resistance of $0.1 \ M \ KCl$ solution in a conductance cell is $300 \ \Omega$ and conductivity is $0.013 \ S \ cm^{-1}$,then the value of cell constant is

$0.0129 \ S \ cm^{-1}$ is equivalent to how many $S \ m^{-1}$ (in $S \ m^{-1}$)?

Identify the factor from the following that does not affect electrolytic conductance of a solution.

Write the formula to calculate conductivity by using a conductivity cell.

The resistance of a $0.5 \, M$ solution of an electrolyte in a cell was found to be $50 \, \Omega$. If the electrodes in the cell are $2.2 \, cm$ apart and have an area of $4.4 \, cm^2$,then the molar conductivity (in $S \, m^2 \, mol^{-1}$) of the solution is: