A xrightarrow{Ag_2O} text{ppt} A xrightarrow{ | vedclass

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(B) reacts with $Ag_2O$ to give a precipitate,indicating it is a terminal alkyne. $A$ undergoes hydration $(Hg^{2+}/H^{+})$ to form $B$,which is reduc

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$CH_3-C \equiv CH$

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(B) reacts with $Ag_2O$ to give a precipitate,indicating it is a terminal alkyne. $A$ undergoes hydration $(Hg^{2+}/H^{+})$ to form $B$,which is reduced by $NaBH_4$ to $C$. $C$ gives turbidity with Lucas reagent $(conc. HCl / ZnCl_2)$ within $5 	ext{ minutes}$,indicating $C$ is a secondary alcohol. $CH_3-C \equiv CH (A) \xrightarrow{Ag_2O} CH_3-C \equiv CAg \downarrow (	ext{ppt})$ $CH_3-C \equiv CH (A)$ $\xrightarrow{Hg^{2+}/H^{+}} CH_3-COCH_3 (B)$ $\xrightarrow{NaBH_4} CH_3-CH(OH)-CH_3 (C)$ $CH_3-CH(OH)-CH_3 (C) \xrightarrow{conc. HCl / ZnCl_2} CH_3-CH(Cl)-CH_3 + H_2O$ (Turbidity within $5 	ext{ minutes}$).

$A \xrightarrow{Ag_2O} \text{ppt}$
$A$ $\xrightarrow{Hg^{2+} / H^{+}} B$ $\xrightarrow{NaBH_4} C$ $\xrightarrow{conc. HCl / ZnCl_2} \text{Turbidity within 5 minutes}$.
Consider the following reactions,'$A$' is:

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$A \xrightarrow{Ag_2O} \text{ppt}$ $A$ $\xrightarrow{Hg^{2+} / H^{+}} B$ $\xrightarrow{NaBH_4} C$ $\xrightarrow{conc. HCl / ZnCl_2} \text{Turbidity within 5 minutes}$. Consider the following reactions,'$A$' is: