Ph^{-}MgCl xrightarrow{text{Hydrolysis}} text | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of a Grignard reagent $(PhMgCl)$ with water (hydrolysis) involves the protonation of the carbanion part of the reagent.The phenyl gro

Vedclass · Accepted Answer

Benzene

Vedclass · Answer

(B) The reaction of a Grignard reagent $(PhMgCl)$ with water (hydrolysis) involves the protonation of the carbanion part of the reagent.The phenyl group $(Ph^-)$ acts as a strong base and abstracts a proton $(H^+)$ from the water molecule $(H_2O)$.The reaction is as follows:$PhMgCl + H_2O \rightarrow C_6H_6 + Mg(OH)Cl$Here,$PhMgCl$ reacts with $H_2O$ to form benzene $(C_6H_6)$ and magnesium hydroxychloride $(Mg(OH)Cl)$.Therefore,the product is benzene.

$Ph^{-}MgCl \xrightarrow{\text{Hydrolysis}} \text{Product}$
Product will be

Similar Questions

Consider the following reaction sequence and identify the major product $P$.
$CH_3CH_2OH$ $\xrightarrow[(ii) KMnO_4]{(i) Jones' Reagent}$ $\xrightarrow[(iii) NaOH, CaO, \Delta]{} P$

Anhydrous sodium acetate on heating with sodalime gives

$A$ mixture of ethyl iodide and $n$-propyl iodide is subjected to Wurtz reaction. The hydrocarbon which will not be formed is

The number of different chain isomers for $C_7H_{16}$ is . . . . . . .

Which of the following is $NOT$ obtained when a mixture of methyl bromide and ethyl bromide is treated with sodium metal in the presence of dry ether?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$Ph^{-}MgCl \xrightarrow{\text{Hydrolysis}} \text{Product}$Product will be