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(C) The reaction sequence is as follows:$1$. $2NaHCO_3 \xrightarrow{\Delta} Na_2CO_3 + H_2O + CO_2(g)$. Here $A = NaHCO_3$,$B = Na_2CO_3$,and $C = CO_

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$pH$ of aqueous solution of both $A$ and $E$ is $7$

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(C) The reaction sequence is as follows:$1$. $2NaHCO_3 \xrightarrow{\Delta} Na_2CO_3 + H_2O + CO_2(g)$. Here $A = NaHCO_3$,$B = Na_2CO_3$,and $C = CO_2$.$2$. $Ca(OH)_2 + CO_2 \rightarrow CaCO_3(milky) + H_2O$. Here $D = CaCO_3$.$3$. $CaCO_3 + H_2O + CO_2 \rightarrow Ca(HCO_3)_2$. Here $E = Ca(HCO_3)_2$.Evaluating the statements:- $A$ is $NaHCO_3$ (Correct).- $B$ $(Na_2CO_3)$ is a metal carbonate soluble in $H_2O$ (Correct).- $D$ is $CaCO_3$ (Correct).- $pH$ of $NaHCO_3$ $(A)$ is basic $(> 7)$ and $Ca(HCO_3)_2$ $(E)$ is also slightly basic $(> 7)$. Thus,the statement that $pH$ is $7$ is incorrect.

$A$ $\xrightarrow{\Delta} B + C_{(gas)}$ $\xrightarrow{Ca(OH)_2} D_{(milky)} + H_2O$ $\xrightarrow{C_{(gas)}} E$. Then the incorrect statement is:

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