A xrightarrow[1% HgSO_4]{20% H_2SO_4} B xri | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction sequence is as follows:$1$. The hydration of an alkyne $A$ in the presence of $HgSO_4$ and $H_2SO_4$ yields a ketone $B$. For phenyla

Vedclass · Accepted Answer

Phenylacetylene

Vedclass · Answer

(A) The reaction sequence is as follows:$1$. The hydration of an alkyne $A$ in the presence of $HgSO_4$ and $H_2SO_4$ yields a ketone $B$. For phenylacetylene $(C_6H_5-C \equiv CH)$,hydration follows Markovnikov's rule to give acetophenone $(C_6H_5-CO-CH_3)$ as the product $B$.$2$. Acetophenone $(C_6H_5-CO-CH_3)$ contains a methyl ketone group,which undergoes the iodoform reaction with $I_2$ and $NaOH$ to produce iodoform ($CHI_3$,product $C$) and sodium benzoate $(C_6H_5COONa)$.$3$. Therefore,the reactant $A$ is phenylacetylene.

$A$ $\xrightarrow[1\% \ HgSO_4]{20\% \ H_2SO_4} B$ $\xrightarrow{I_2 + NaOH} C + C_6H_5COONa$. The reactant $A$ is

Similar Questions

$CH_3 - C \equiv C - CH_3 \xrightarrow[CH_3COOH]{BH_3, THF} \text{Major product}$

Final product of the reaction
$CH_3-CH=CH_2$ $\xrightarrow[CCl_4]{Br_2} A$ $\xrightarrow[(3 \ mol)]{NaNH_2} B$ $\xrightarrow{CH_3-Br} C$ $\xrightarrow[Pd-BaSO_4]{H_2} D$

Choose the correct set of reagents for the following conversion:
$trans-(Ph-CH=CH-CH_3) \rightarrow cis-(Ph-CH=CH-CH_3)$

Which is the most reactive hydrocarbon among the following?

$2-$pentyne on reaction with sodium in liquid ammonia produces compound $A$. What is $A$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module