$N_2 + 3H_2 \to 2NH_3$. If the concentration of $NH_3$ changes from $0.01 \ M$ to $0.04 \ M$ in $20 \ seconds$,then the rate of reaction will be:

  • A
    $1.5 \times 10^{-3} \ M \ sec^{-1}$
  • B
    $0.75 \times 10^{-3} \ M \ sec^{-1}$
  • C
    $2 \times 10^{-3} \ M \ sec^{-1}$
  • D
    $3 \times 10^{-3} \ M \ sec^{-1}$

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