CH_3-CH_2-CH_2-Cl xrightarrow{Na, text{Dry et | vedclass

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(C) $1$. The reaction $CH_3-CH_2-CH_2-Cl \xrightarrow{Na, 	ext{Dry ether}}$ is a Wurtz reaction. However,with $n$-propyl chloride,it primarily yields

Vedclass · Accepted Answer

Benzene

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(C) $1$. The reaction $CH_3-CH_2-CH_2-Cl \xrightarrow{Na, 	ext{Dry ether}}$ is a Wurtz reaction. However,with $n$-propyl chloride,it primarily yields $n$-hexane $(CH_3-CH_2-CH_2-CH_2-CH_2-CH_3)$ as $P$.$2$. The second step involves the aromatization of $n$-hexane using $V_2O_5$ and $Al_2O_3$ at high temperature $(\Delta)$.$3$. $n$-Hexane undergoes cyclization and dehydrogenation to form benzene $(C_6H_6)$ as $Q$.$4$. Therefore,$Q$ is benzene.

$CH_3-CH_2-CH_2-Cl$ $\xrightarrow{Na, \text{Dry ether}} P$ $\xrightarrow[V_2O_5, Al_2O_3]{\Delta} Q$. $Q$ is

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